(y^2-8)(5y^2-2y+1)=

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Solution for (y^2-8)(5y^2-2y+1)= equation: 


Simplifying
(y2 + -8)(5y2 + -2y + 1) = 0

Reorder the terms:
(-8 + y2)(5y2 + -2y + 1) = 0

Reorder the terms:
(-8 + y2)(1 + -2y + 5y2) = 0

Multiply (-8 + y2) * (1 + -2y + 5y2)
(-8(1 + -2y + 5y2) + y2(1 + -2y + 5y2)) = 0
((1 * -8 + -2y * -8 + 5y2 * -8) + y2(1 + -2y + 5y2)) = 0
((-8 + 16y + -40y2) + y2(1 + -2y + 5y2)) = 0
(-8 + 16y + -40y2 + (1 * y2 + -2y * y2 + 5y2 * y2)) = 0
(-8 + 16y + -40y2 + (1y2 + -2y3 + 5y4)) = 0

Combine like terms: -40y2 + 1y2 = -39y2
(-8 + 16y + -39y2 + -2y3 + 5y4) = 0

Solving
-8 + 16y + -39y2 + -2y3 + 5y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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